Pretty sure the answer is just "40 minutes" and it is a question to make someone think about what they are doing rather than automatically solve every task.
IIRC the speed of the 9th symphony is somewhat controversial because what markings we have on original sheetmusic are significantly faster than it's normally played.
Symphony music in general is going to vary a decent bit depending on what bpm(s) the conductor is choosing.
I'd like to think it's a really clever question about making people verify what's written before them, rather than taking everything at face value and absolute fact.
This is similar to something I assumed right before I had a long argument with a high school physics teacher. We ended up agreeing that he just didn't really care.
For anyone who hasn't read The Mythical Man-Month, it is a timeless, compelling, relevant book on software engineering and project management. It is also accessible to non-technical audiences with lessons that apply across much of modern workforces.
With something like a baby, people know what's going on and what's meant. That's why it's the example. But when it comes to esoteric things, playing word games just confuses the issue and will lead to a manager thinking that indeed 9 woman can give you a baby in 1 month (I'm not jumping through your word games, you know what's meant).
Why couldn't 9 women deliver a baby in one month? That's perfectly reasonable. Put the baby in a vehicle. Drive. Maybe stop at some hotels or just sleep in the vehicle with all 9 women. Then eventually you reach your destination in 1 month. Deliver baby. Profit.
My kid showed me a test question from a junior high math test about construction a building in 12 months with x number of workers, how many workers do they need to hire if they want it done in 6 months.
So I guess if you answer that question "wrong" youd be smart, and if you answer it right, management. Even a junior high student mocked it...
Well, if T is total time to build, D is the time that can be distributed equally among any number of workers, and C is constant, indivisible time extra time that goes along with construction, and X is the number of workers, then:
T - C = D / X
so, since T is 12 and 6 is half of 12, then:
T/2 - C = D/X * 1/2
or
T/2 - C = D/2X where X > 0, C = 0, T=12, and D = (T - C) / X
which is both the answer it's looking for (twice as many workers) and the correct answer (it depends on at least two things we don't know), while assuming what they're assuming, which is C = 0
(Stupid ass junior high math problems piss me off, junior high is a traumatic experience)
I feel like a lot of the puzzles in Professor Layton games are like this. Any time you find yourself starting some complex algebra or multiplication, you need to consider rereading the problem and seeing if you just need to pick a number that’s there.
For example: A bus can travel 100 miles on a full tank with its full passenger load of 80 people. If everyone gets off the bus, then how far can it travel?
The answer
0 miles. With everyone off, there’s no one to drive it.
Snopes says this is "undetermined" (also that CDs hold 74 minutes). Honesty pleasently surprised by how plausible it is from the given evidence though, I was expecting this to turn out to be definitively a myth.
I did orchestra as student, and there's so much you get out of watching the conductor, way more than the downbeat, and a good conductor, orchestra relationship can get to the point subtle nuances effect how you play, and I just imagine a guy trying to conduct and hold his cheeks closed, and the whole rushed performance sounding absurd with unintentional volume and speed changing abruptly all over the place.
It is. The original worksheet it's cropped from says "beware, one of these is a trick question!", but obviously that was cropped out because someone really wanted to create an opportunity to feel superior to someone.
Reminds me of an animator saying ''If a pregnant woman takes nine months to have a baby, can four women have a baby in two and a half months?''
The point is, somethings can't be done faster through simple numbers. Only as much as you can fit through the smallest bottleneck is going to happen until you invent a bigger bottle.
Most speedrunners know about the glitch in Beethoven's 9th where if you have the entire brass section make a quarter turn to the left at just the right moment of the open fifths the whole symphony freezes for a second and then drops you straight into the Ode to Joy.
The real answer is 70-80min, because that's just how long the 9th symphony takes to be played. And they better add a chorus as well, otherwise the 4th movement won't be as good as it normally is
Let’s say you put like 1000 violinists all in a big, long row. Then, have the first violinist play a note, then the second plays the very same note, then the third, and so on. Let’s say you could also time it so that at the very moment the sound wave from one violinist hits the next is when that one plays the note. Brrrrrrump! All the way across. Let’s also say you could time it perfectly so that the waves don’t cancel each other out. What would happen?
I think eventually you reach a point where previously played notes would lose all of their energy, meaning there's probably an upper limit on how loud it would get for an observer at the end. Something something Doppler effect.
Not the Doppler effect, as that only applies to moving objects, but instead the inverse square law, where the energy of the sound wave decreases by the square of the distance from the origin, since it spreads in a sphere with the energy being spread across the surface of the sphere, resulting in a very quick dropoff in the loudness.
As I was going to St. Ives I met a man with seven wives. Each wife had 7 sacks, each sack had 7 cats, each cat had 7 kits. Kits, cats, sacks, wives; how many were going to St. Ives?
This is a stupid riddle, because maybe they were walking in the same direction. I'd expect the guy with all the wives and cats to be making slower progress, you know?
We need a player for every note in the score(tied notes can be played by a single musician). On the conductor's downstroke everyone plays their note. Every note of the 9th played simultaneously. I want to hear this, but I don't think that my poor old computer would function if I opened that many individual instruments in Reason.
Just put the orchestra on a spaceship approaching light speed, and you can take even less time (relatively experienced by an off-spaceship audience.) If you still want the shockwave, you can use an Alcubierre drive.
The answer could be however many beats the longest note is at however many BPM you choose given that 60 is a large enough number to cover each pitch and quality of note in the piece. Having all the essential notes and durations covered, the rest is just inessential noodling left as an exercise for the reader.