Discard 8pin now, draw 7sou and discard 5pin, you're tenpai waiting on 5sou
Holy shit you're right. Now I see it, thanks. Was it easy for you to see? Let me know if you have tips. I always look for 5 blocks, but here those that I saw were 333pin, 566pin, 23sou, 44sou and 668sou...
Idk I also just applied 5 block method but came to a different conclusion than you. 333pin, 5668pin (expecting 2), 234sou, 4668sou (expecting 2). I gave the solution that reduces 5668pin group to one block because that's what the game is suggesting, but you can do the same with the sous instead by discarding 8sou now, draw 7pin and discard 4sou, now tenpai waiting on 4/7pin
I don't see why you split 234sou because that's literally already complete, I wouldn't even consider using 4sou as the head unless I draw another 4sou or I draw 1sou, even then I'd discard 1sou to preserve tanyao especially when there are other head candidates in the hand already
Edit: another thing to keep in mind, open waits are strong but they're not as strong as you think if you already have 2 of the tiles you need in hand. 6 tile acceptance is still better than 4 of edge/closed waits, but in this specific case, if you actually wanted to go for tanyao then it's actually 2 tile acceptance, and if you discard 1sou at any point to preserve tanyao you would be in furiten
