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🌚 - 2024 DAY 4 SOLUTIONS - 🌚

Day 4: Ceres Search

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34 comments
  • Kotlin

    fun part1(input: String): Int {
        return countWordOccurrences(input.lines())
    }
    
    fun part2(input: String): Int {
        val grid = input.lines().map(String::toList)
        var count = 0
        for (row in 1..grid.size - 2) {
            for (col in 1..grid[row].size - 2) {
                if (grid[row][col] == 'A') {
                    count += countCrossMatch(grid, row, col)
                }
            }
        }
        return count
    }
    
    private fun countCrossMatch(grid: List<List<Char>>, row: Int, col: Int): Int {
        val surroundingCorners = listOf(
            grid[row - 1][col - 1], // upper left
            grid[row - 1][col + 1], // upper right
            grid[row + 1][col - 1], // lower left
            grid[row + 1][col + 1], // lower right
        )
        // no matches:
        //   M S   S M
        //    A     A
        //   S M   M S
        return if (surroundingCorners.count { it == 'M' } == 2
            && surroundingCorners.count { it == 'S' } == 2
            && surroundingCorners[0] != surroundingCorners[3]
        ) 1 else 0
    }
    
    private fun countWordOccurrences(matrix: List<String>): Int {
        val rows = matrix.size
        val cols = if (rows > 0) matrix[0].length else 0
        val directions = listOf(
            Pair(0, 1),   // Horizontal right
            Pair(1, 0),   // Vertical down
            Pair(1, 1),   // Diagonal down-right
            Pair(1, -1),  // Diagonal down-left
            Pair(0, -1),  // Horizontal left
            Pair(-1, 0),  // Vertical up
            Pair(-1, -1), // Diagonal up-left
            Pair(-1, 1)   // Diagonal up-right
        )
    
        fun isWordAt(row: Int, col: Int, word: String, direction: Pair<Int, Int>): Boolean {
            val (dx, dy) = direction
            for (i in word.indices) {
                val x = row + i * dx
                val y = col + i * dy
                if (x !in 0 until rows || y !in 0 until cols || matrix[x][y] != word[i]) {
                    return false
                }
            }
            return true
        }
    
        var count = 0
    
        for (row in 0 until rows) {
            for (col in 0 until cols) {
                for (direction in directions) {
                    if (isWordAt(row, col, "XMAS", direction)) {
                        count++
                    }
                }
            }
        }
    
        return count
    }
    
34 comments