Is it possible to constrain a rectangle to be concentric with another rectangle?
Is it possible to constrain a rectangle to be concentric with another rectangle?
I have the following:
I want the center rectangle to be concentric with the outer rectangle (the separation of each edge should be equal). What's the best way to do this?
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There are several ways to do it!
Assuming you already have rectangle contraints -- horizontal, vertical, width, height, etc. -- then I'd probably constrain the centers to be coincident.
Personally, I hate defining the same thing more than once, so I'd use parameters (variables). Constrain one with height and width equal to parameters, and constrain the other based on 80% of the dimensions. Then you offset two adjacent edges by 10% of the size, and you're golden. (Keep in mind kerf, etc, if necessary).
Assuming you already have rectangle contraints – horizontal, vertical, width, height, etc. – then I’d probably constrain the centers to be coincident.
Yeah, you can see all those constraints in the picture.
Constrain one with height and width equal to parameters, and constrain the other based on 80% of the dimensions.
Ah, okay - this is more or less the way that I usually do it. If its a box, the concentric separation, or "wall thickness" would be the same, so I would set a vertical and horizontal distance constraint between the outer and inner rectangles. This just felt sort of hacky to me, so I was wondering if there was a dedicated constraint so that I could, for example, select the outer rectangle, and the inner rectangle, then click a "Constrain concentric" option. Then I would only need one constraint for the wall thickness.
I'm by no means a FreeCAD expert, so it's possible there are better options.
If you're using parameters -- specifically the same parameters for both rectangles -- then it should be as simple as making a coincident contraint on the center points.