C++ @programming.dev lysdexic @programming.dev 2mo ago

How to avoid one C++ foot gun

C++'s implicit copy and move behavior offer an excellent way to shoot yourself in the foot. Here's an example of how they can create a double-free and how to avoid it.

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I got stuck on cheese counting:

inventory.count(cheeseName) == 1 ? "Yes" : "No"

1 cheese == some, 2 cheese == none :/
- Yeah, that's confusing to read. A hashset can only contain at most one of each cheese kind, in c++20 you can write inventory.contains(cheeseName), before that you had to use .count or inventory.find(cheeseName) != inventory.end() or something like that

15 comments