Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
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import { AdventOfCodeSolutionFunction } from "./solutions";
/**
* this function evaluates the
* @param levels a list to check
* @returns -1 if there is no errors, or the index of where there's an unsafe event
*/
export function EvaluateLineSafe(levels: Array<number>) {
// this loop is the checking every number in the line
let isIncreasing: boolean | null = null;
for (let levelIndex = 1; levelIndex < levels.length; levelIndex++) {
const prevLevel = levels[levelIndex - 1]; // previous
const level = levels[levelIndex]; // current
const diff = level - prevLevel; // difference
const absDiff = Math.abs(diff); // absolute difference
// check if increasing too much or not at all
if (absDiff == 0 || absDiff > 3)
return levelIndex; // go to the next report
// set increasing if needed
if (isIncreasing === null) {
isIncreasing = diff > 0;
continue; // compare the next numbers
}
// check if increasing then decreasing
if (!(isIncreasing && diff > 0 || !isIncreasing && diff < 0))
return levelIndex; // go to the next report
}
return -1;
}
export const solution_2: AdventOfCodeSolutionFunction = (input) => {
const reports = input.split("\n");
let safe = 0;
let safe_damp = 0;
// this loop is for every line
main: for (let i = 0; i < reports.length; i++) {
const report = reports[i].trim();
if (!report)
continue; // report is empty
const levels = report.split(" ").map((v) => Number(v));
const evaluation = EvaluateLineSafe(levels);
if(evaluation == -1) {
safe++;
continue;
}
// search around where it failed
for (let offset = evaluation - 2; offset <= evaluation + 2; offset++) {
// delete an evaluation in accordance to the offset
let newLevels = [...levels];
newLevels.splice(offset, 1);
const newEval = EvaluateLineSafe(newLevels);
if(newEval == -1) {
safe_damp++;
continue main;
}
}
}
return `Part 1: ${safe} Part 2: ${safe + safe_damp}`;
}
God, I really wish my solutions weren't so convoluted. Also, this is an O(N^3) solution....
I think it could be maybe O(n^2) because the other for loop which tries elements around the first error will only execute a constant of 5 times in the worst case? I'm unsure.
If you look at each of the levels of all reports, you will access it a constant number of times: at most twice in each call to EvaluateLineSafe, and you will call EvaluateLineSafe at most six times for each report.
It really depends on what your parameter n is. If the only relevant size is the number of records (let's say that is n), then this solution takes time in O(n), because it loops over records only once at a time. This ignores the length of records by considering it constant.
If we also consider the maximum length of records (let's call it m), then your solution, and most others I've seen in this thread, has a time complexity in O(n * m^2) for part 2.