In the bottom gap, either side of the 1 being a bomb causes the 1,2,4 corner to be a bomb.
If the bomb is right of the 1, then the square above and below the 4 must be bombs because of the 2.
If the bomb is to the left of 1, the 2,2,3,3 forces one of the squares below the second 2 to be a bomb, which means the square below the 4 must be safe, so the square above 4 must be a bomb.
No, the 3 below the two 1s has a shared partner with the 2 to it's left. So because it has a bomb directly above it, it must have one more below it. Therefore the space under the 4 would be empty and the space above it would have to be a bomb for the upper 2.